Question

(sqrt3-sqrt2)*qwrt72/3(2sqwrt6-sqrt16)(^3sqrt64+1)

Answer 1

$(sqrt3-sqrt2)*frac{sqrt{72}}{3(2sqrt6-sqrt16)}(sqrt[3]{64}+1)=$

$=(sqrt3-sqrt2)*frac{sqrt{36*2}}{3(2sqrt6-4)}(4+1)=(sqrt3-sqrt2)*frac{sqrt{36}*sqrt2}{6(sqrt6-2)}}*5=$

$(sqrt3-sqrt2)*frac{sqrt{36}*sqrt2}{6(sqrt6-2)}}*5=(sqrt3-sqrt2)*frac{6*sqrt2}{6(sqrt3*sqrt2-(sqrt2)^2)}}*5=$

$=(sqrt3-sqrt2)*frac{sqrt2}{sqrt2(sqrt3-sqrt2)}}*5=5$

 

 

 

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