Question

Решите пожалуйста.
a)(a-b)^2/(b-a)^2
б)12a^3b^5(p-q)^2/36a^2b(q-p)^2
в)16(x-y)^2/48(y-x)^2
г)49xy(c-d)^2/7x^2(d-c)^2

Answer 1

$frac{(a-b)^2}{(b-a)^2} = frac{a^2-2ab+b^2}{b^2-2ab+a^2}=1\\ frac{12a^3b^5(p-q)^2}{36a^2b(q-p)^2} = frac{ab^4(p^2-2qp+p^2)}{3(q^2-2qp+p^2)} = frac{ab^4}{3}\\ frac{16(x-y)^2}{48(y-x)^2}= frac{x^2-2xy+y^2}{3(y^2-2xy+x^2)}=1/3\\ frac{49xy(c-d)^2}{7x^2(d-c)^2}= frac{7y}{x}$