Question

Разложите на множители x²y²-4xy-20y-25y²

Answer 1

(x²y²-25y²)-(4xy+20y)=y²(x²-25)-4y(x+5)=y²(x-5)(x+5)-4y(x+5)=
(x+5)(y²(x-5)-4y)=(x+5)(y²x-5y²-4y)

Answer 2

x²y²-4xy-20y-25y²=(x²y²-25y²)-(4xy+20y)=y²(x²-25)-4y(x+5)=
=y²(x-5)(x+5)-4y(x+5)=(x+5)(y²x-5y²-4y)