Предмет: Химия, автор: ilrav

Сколько молекул азота содержится в 280г молекулярного азота-N2

Ответы

Автор ответа: boym2002

0

n=m/M
280/28=10(моль)
N=n*(6,02*10^23)(постоянная Авогадро)
10*(6,02*10^23)=6,02*10^24
Ответ: 6,02*10^24

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