Question

log16 (x^2-2x-3)^2-2 log16(x^2+x-2)=1/2

Answer 1

2log16((x^2-2x-3)/(x^2+x-2))=1/2

(x^2-2x-3)/(x^2+x-2)=2
x^2-2x-3=2x^2+2x-4
x^2+4x-1=0
x1=-2+sqrt(5)
x2=-2-sqrt(5)
одз: $xneq(-2;3)$
x=-2-sqrt(5)