Предмет: Геометрия, автор: Аннабель11111

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Автор ответа: dnepr1

4) Обозначим ОО₁ как х.
Тогда площадь заданного четырёхугольника равна разности площадей треугольников АМВ и АОВ.
S = (1/2)*(25+x)*60 - (1/2)*x*60 =
= (1/2)*60*(25 + x - x) = 30*25 = 750 мм².

5) Срединный перпендикуляр - это отрезок СС₁.

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