Question

Разложите на множетели
Х²-у²-1,5*(х-у)
4а²-в²-2а+в
А²+6а+6в-в²

Answer 1

(a^2 - b^2 )+ (6a + 6b) =(a - b)(a + b) + 6(a + b) = (a + b)(a - b + 6)

(4a^2 - b^2) + ( b - 2a) = (2a - b)(2a + b) - (2a - b) = (2a - b)(2a + b - 1)

(x^2 - y^2) - 1,5(x - y) = (x - y)(x + y) - 1,5(x - y) = (x - y)(x + y - 1,5)