Question

(b*b-8b+7):(b*b-2b-35)

Answer 1

$b^{2} -8b+7 = (b-1)(b-7) \\ b^{2} -2b-35=(b+5)(b-7) \\ \frac{ (b-1)(b-7)}{(b+5)(b-7)} = \frac{b-1}{b+5}$