Question

Сократите дробь:
a)$\frac{ t^{2}-36 }{6+t}$
б)$\frac{5k-2l}{ 25k^{2}-4l^{2}}$

Answer 1

а) t²-36 / 6+t = (t-6) (t+6) / 6+t = t-6
б) 5к-2i / 25k²-4i² = 5k-2i / (5k-2i) (5k+2i) = 1/ (5k+2i)