Question

sin ^6x +cos^2x =1 решите уравнение

Answer 1

sin^6x+cos^2x-1=0
sin^6x-sin^2x=0
sin^4x(sin^2x-1)=0
sin^4=0
sinx=0
x=Πn, n€Z
sin^2x-1=0
sinx=+-1
x=+-Π/2+2Πk, k€Z
Ответ: +-Π/2+2Πk, k€Z; Πn, n€Z