Question

Решите уравнение cos*(п/3-2x)=1/2.

Answer 1

$\cos\left(\dfrac{\pi}{3}-2x\right)=\dfrac{1}{2}\\ \dfrac{\pi}{3}-2x=-\dfrac{\pi}{3}+2k\pi \vee \dfrac{\pi}{3}-2x=\dfrac{\pi}{3}+2k\pi\\ 2x=\dfrac{2\pi}{3}-k\pi \vee 2x=-k\pi\\ x=\dfrac{\pi}{3}-k\pi \vee x=-k\pi\\ \Updownarrow\\ \boxed{x=\dfrac{\pi}{3}+k\pi \vee x=k\pi, k\in \mathbb{Z}}$