Предмет: Геометрия, автор: tashka3807

В треугольнике ABC угол С равен 90, AB=10. AC= корень из 91. Найдите косинус внешнего угла при вершине B.

Ответы

Автор ответа: em0angel

По формуле : cos в квадрате = 1-sin в квадрате. SinB= корень 9110. Получается 0.3, а ответ -0.3 , т.к. Нам надо было найти смешные,т.е. Внешний

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