Question

Помогите, решите!!1(( A (6a-90k)^2= Б (-3+2x)^2= B (mn-23)(mn+23)= Г (2tz+t^2)(4t^2z^2-2t^3z+t^4)=

Answer 1

$(6a-90k)^2=36a^2-1080ak+8100k^2\\(-3+2x)^2=9-12x+4x^2\\(mn-23)(mn+23)=m^2n^2-529\\(2tz+t^2)(4t^2z^2-2t^3z+t^4)=8t^3z^3+t^6$