Question

решить уравнение (x-4) (4x-3) = -3

Answer 1

(x-4)*(4x-3)=-3
4x²-16x-3x+12=-3
4x²-19x+15=0
D=(-19)²-4*4*15=361-240=121
$x_{1} = frac{-(-19)- sqrt{121} }{2*4} , x_{1} =1 x_{2} = frac{-(-19)+ sqrt{121} }{2*4} , x_{2} =3,75$