Question

решить f'(x)=0. если f(x)=8x^3-3x^2+25

Answer 1

f'(x)=24x^2-6x
f'(0)=0

Answer 2

$f(x)=8x^3-3x^2+25;\\f'(x)=24x^2-6x;\\f'(x)=0;\\24x^2-6x=0;\\6x(4x-1)=0;\\x_1=0;\\4x-1=0;x_2=frac{1}{4}=0.25$