Question

(x^3+y^2)^2
(x+2)^3-(x-2)^3

Answer 1

($x^{3}$+$y^{2}$)^2=$(x^{3}) ^{2} +2* x^{3} * y^{2} + (y^{2}) ^{2}= x^{6}+2 x^{3} y^{2}+ y^{4}$
(x+2)^3-(x-2)^3=$x^{3}+ 8-( x^{3} -8)= x^{3} +8- x^{3} +8=16$