Question

Решите срочно номер 4

Answer 1

№4
$\frac{b^2+8b+16}{4b+16} = \frac{(b+4)^2}{4(b+4)} = \frac{b+4}{4}$

$\frac{b^2-16}{2b+8} = \frac{(b-4)(b+4)}{2(b+4)} = \frac{b-4}{2}$