Question

решите уравнение (3b-2)^2-(b+1)^2=0

Answer 1

$(3b-2)^2-(b+1)^2=0$

$(3b-2-b-1)(3b-2+b+1)=0$

$(2b-3)(4b-1)=0$

$b_{1} =1,5$

$b_{2} = \frac{1}{4}$