Question

разложить на множители

Answer 1

х^2(b-1)-y(1-b)=x^2(b-1)+y(b-1)=(b-1)(x^2+y)
7a^2b^2+14a^3b-28ab^3=7ab(ab+2a^2-4b^2)
b^3(a-2)+4a(2-a)+3(a-2)=b^3(a-2)-4a(a-2)+3(a-2)=(a-2)(b^3-4a+3)
4x^2y-4xy^2-y+x=(4x^2y+x)-(4xy^2+y)=x(4xy-1)-y(4xy+1)=(4xy+1)(x-y)