Question

разложите на множители 1)x^2n-9; 2)a^2c^4-9; 3)(3x-1)^2-(4x+3)^2

Answer 1

$x^{2n} -9=( x^{n} ) ^{2} - 3^{2} =( x^{x}-3 )*( x^{n}+3 ) a^{2}c^{4} -9=( a} c^{2} )^{2} -3^{2} =(ac^{2}-3) *(ac^{2} +3)$

(3x-1)²-(4x+3)²=(3x-1-(4x+3))*(3x-1+4x-3)=(-x-4)*(7x-4)