Question

y=1/sinx найти производную

Answer 1

$displaystyle boxed{(frac{u}{v})'=frac{u'v-uv'}{v^2}}\ (frac{1}{sinx})'= frac{1'sinx-1 cdot sinx'}{sin^2x}= frac{0-cosx}{sin^2x} = bf{-frac{cosx}{sin^2x}}$