Question

Помогите, пожалуйста, со 2ым номером

Answer 1

$limlimits _{n to infty} frac{1}{3n-2} =[ frac{1}{infty } ]=0\\ limlimits _{n to infty} (3-2cdot ( frac{5}{6})^{n})= left { {{3-2cdot 0=3; ,; esli; nto +infty } atop {3-2cdot (+infty )=-infty ; ,; esli; nto -infty }} right. \\ limlimits _{n to infty} frac{7n+3}{5n-3} = limlimits _{n to infty}frac{7+frac{3}{n}}{5-frac{3}{n}} = frac{7+0}{5-0} = frac{7}{5}$