Question

x-1:x+2 + x:x-2 = 8:x2-4

Answer 1

((x-1)(x-2)+x(x+2))/(x²-4)-(8/(x²-4)=0
(x²-2x-x+2+x²+2x)-8)/(x²-4)=
=0
2x²-x-6=0
D=b²-4ac(a=2,b=-1,c=-6)
D=1+48=49=7²
x1,x2=(-b+-корень изD)/2a
x1=(1-7)/4=(-6)/4= -1.5
x2=(1+7)/4=8/4=2
ответ: x=2