Question

сократите (3n-1)!/(3n+2)!; (n-2)!/(n+1)!

Answer 1

$frac{(3n-1)!}{(3n+2)!}= frac{(3n-1)!}{(3n-1)!*3n*(3n+1)(3n+2)}= frac{1}{3n(3n+1)(3n+2)}$

$frac{(n-2)!}{(n+1)!}= frac{(n-2)!}{(n-2)!((n-1)n(n+1)}= frac{1}{n(n^2-1)}$