Question

помогите решить cos^2 3x=1/2

Answer 1

$cos^23x=frac{1}2\cos3x=бfrac{sqrt2}2\\ left[begin{array}{ccc}cos3x=frac{sqrt2}2\cos3x=-frac{sqrt2}2end{array}right= textgreater left[begin{array}{ccc}3x=бfrac{pi}4+2pi n;nin Z\3x=бfrac{3pi}4+2pi n;nin Zend{array}right= textgreater \\\= textgreater 3x=бfrac{pi}4+pi n;nin Z= textgreater x=бfrac{pi}{12}+frac{pi n}3;nin Z$