Question

Дана функция f(x)=6ln(1/3*x).Найдите f'(x);f'(1/3) HELP PLZ

Answer 1

ln (x/3) = ln x - ln3, derivacie(proizvodnaja)=1/x
f´(x) = 6. 1: (x/3) .1/3 = 6.1/x=6/x
f´(1/3) = 6/(1/3) = 6.3 = 18