Question

1/6х-4у-1/6х+4у-3х/4у^2-9x^2

Answer 1

$frac{1}{6x-4y} - frac{1}{6x+4y} - frac{3x}{4y^{2} -9 x^{2} } = frac{1}{2*(3x-2y)} - frac{1}{2*(3x+2y)} + frac{3x}{(3x-2y)*(3x+2y)}$$= frac{3x+2y-(3x-2y)+6x}{2*(3x-2y)*(3x+2y)}= frac{4y+6x}{2*(3x-2y)*(3x+2y)} = frac{2*(2y+3x)}{2*(3x-2y)*(3x+2y)} = frac{1}{3x-2y}$