Question

a-3/4a квадрат+ 24a+36:(a/3a-9-3/a квадрат+ 3a+ a квадрат+9/27-3a квадрат)

Answer 1

1)a/3(a-3)-3/a(a+3)-(a²+9)/3(a-3)(a+3)=
=(a³+3a²-9a+27-a³-9a)/3a(a-3)(a=3)=(3a²-18a+27)/3a(a-3)(a+3)=
=3(a²-6a+9)/3a(a-3)(a+3)=3(a-3)²/3a(a-3)(a+3)=(a-3)/a(a+3)
2)(a-3)/4(a+3)²:(a-3)/a(a+3)=(a-3)/4(a=3)²*a(a+3)/(a-3)=a/4(a+3)