Question

2x⁴-2x²=3,2(Три, вторые)

Answer 1

$2 x^{4} -2 x^{2} = frac{3}{2} x^{2} =t, t geq 0. 4t^{2} -4t-3=0. D=(-4)^2-4*4*(-3)=16+48=64=8^2. t_{1}= frac{4+8}{8} = frac{3}{2}. t_{2} = frac{4-8}{8} = frac{-1}{2} . x^{2} = frac{3}{2}  .$$x_1= sqrt{ frac{3}{2} } x_2= -sqrt{ frac{3}{2} }$