Question

1)2cos x = √3
2)tg x =√3
3)ctg=√3

Answer 1

1) 2cosx=√3
cosx=√3/2
x=+-arccos√3/2+2Πn, n€Z
x=+-Π/6+2Πn, n€Z
2) tgx=√3
x=arctg√3+Πm, m€Z
x=Π/3+Πm, m€Z
3) ctgx=√3
x=arcctg√3+Πk, k€Z
x=Π/6+Πk, k€Z