Question

Помогите решить Систему неравенств N1587

Answer 1

$displaystylettleft { {{frac{0,6x+6}{3}-frac{0,2x+1}{2}>1} atop {frac{4-3x}{2} >5}} right. left { {{|cdot6} atop {|cdot2}} right. left { {{1,2x+12-0,6x-3>6} atop {4-3x>10}} right. left { {{0,6x>-3} atop {-3x>6}} right. left { {{x>-5} atop {x<-2}} right. \left { {{-(-5)++++++++>x} atop {++++++++(-2)->x}} right. \xin(-5;-2)$

Ответ: $(-5;-2)$

$displaystylett left { {{frac{0,8x-1}{5}-frac{1}{2}xleq 0,48 } atop {frac{x-5}{3}-1leq frac{x}{6} }} right. left { {{|cdot10} atop {|cdot6}} right. left { {{1,6x-2-5xleq4,8 } atop {2x-10-6leq x }} right.left { {{-3,4xleq 6,8} atop {xleq 16}} right.left { {{xgeq -2} atop {xleq16 }} right. \left { {{-[-2]++++++>x} atop {++++++[16]->x}} right. \xin[-2;16]$

Ответ: $[-2;16]$

$displaystylettleft { {{frac{0,2x-1}{7}-frac{0,3x}{2} leq0,1 } atop {frac{x+1}{3}-1leq frac{x}{4}}} right. left { {{|cdot14} atop {|cdot12}} right. left { {{0,4x-2-2,1xleq1,4 } atop {4x+4-12leq3x }} right. left { {{-1,7xleq 3,4} atop {xleq8}} right. left { {{xgeq-2 } atop {xleq 8}} right. \left { {{-[-2]++++++>x} atop {+++++++[8]->x}} right. \xin[-2;8]$

Ответ: $[-2;8]$

$displaystylettleft { {{frac{1,4-x}{5}-frac{0,6x}{3}<2,28 } atop {frac{2x-1}{7}-1>frac{x}{3}}} right. left { {{|cdot15} atop {|cdot21}} right. left { {{4,2-3x-3x<34,2} atop {6x-3-21>7x}} right. left { {{-6x<30} atop {-x>24}} right. left { {{x>-5} atop {x<-24}} right. \left { {{-------(-5)+>x} atop {+(-24)------>x}} right. \xinemptyset$

Ответ: решения нет