Question

log(9x) 27 = 1/log(3) x

Answer 1

x>0
3/(log(3)x+2)-1/log(3)x=0
(3log(3)x-log(3)x-2)/log(30x(log(3)x+2)=0
2(log(30x-1)/log(3)x(log(30x+2)=0
log(30x=a
2(a-1)/a(a+2)=0
a=1  ⇒log(3)x=1⇒x=3