Question

$3 x^{2} +8x-3=0$ помогите плизз.

Answer 1

$3x^2+8x-3=0$

$D=64+36=100$

$x1= frac{(-8+10)}{6} = frac{2}{6} = frac{1}{3}$

$x_{2} = frac{(-8-10)}{6}=- frac{18}{6} =-3$

Ответ:$x_{1} x= frac{1}{3} | x_{2} =-3$