Question

y^3-2y^+3y-6=0 РЕШИТЕ

Answer 1

y^3-2y^2+3y-6=0
(y^3-2y^2)+(3y-6)=0
y^2(y-2) +3(y-2)=0
(y-2)(y^2+3)=0
y-2=0      y^2+3=0
y=2         y^2=-3 - корней нет
Ответ:2

Answer 2

$y^3-2y^2+3y-6=0 \ y=б1;б2;б3;б6 \ y(1)=1-2+3-6 neq 0 \ y(-1)=-1-2-3-6 neq 0 \ y(2) = 8-8+6-6=0 \ frac{y^3-2y^2+3y-6}{y-2} = y^2+3 \ (y^2+3)(y-2)=0 \ y^2+3 neq 0 ; y^2 geq 0 \ y-2=0 ; y=2$