Question

представь в виде дроби: a)8/b+6/c b)5/7a-3/7 в)2/x2+3a/5x г)8/xy+9a/2xc

Answer 1

a)$frac{8}{b} + frac{6}{c} = frac{8c}{bc} + frac{6b}{bc} = frac{8c+6b}{bc}  b)$$frac{5}{7a} - frac{3}{7} = frac{5-3a}{7a}$ 
 в)$frac{2}{x^{2} } + frac{3a}{5x} = frac{10}{5 x^{2} } + frac{3ax}{5 x^{2} } = frac{10+3ax}{5 x^{2} }$
г)$frac{8}{xy} + frac{9a}{2xc} = frac{16xc}{2 x^{2} cy} + frac{9axy}{2 x^{2} cy} = frac{16xc+9axy}{2 x^{2} cy}$