Question

1)-0,36-x²=0

2)16x+64=-x²

3)13x+3x²=-14

4)7x²-3x=0

5)5=2x-x²

6)16+x²=8x

7)1-4x²+3x=0

8)10x²-2=x

Answer 1

1) $-0,36-x^2=0, x^2 = -0,36$ Нет решения. Т.к. квадрат всегда положителен.

2) $16x+64=-x^2, (x + 8)^2=0, x_1=x_2=-8$

3) $13x+3x^2=-14, 3x^2+13x+14=0,\ D = 169 - 168 = 1,\ x_1 = (-13+1)/6 = -2, x_2 = -(-13-1)/6 = -7/3$

4) $7x^2-3x=0, x(7-3x) = 0, x_1 = 0, x_2 = 7/3$

5)$5=2x-x^2, -x^2+2x-5=0$, корней нет, так как $D=4-20=-16<0$

6) $16+x^2=8x, x^2-8x+16 = (x-4)^2, x_1 = x_2 = 4$

7)$1-4x^2+3x=0, (x-1)(x+1/4) = 0, x_1 = 1, x_2 = -1/4$

8)$10x^2-x-2=0, D = 1 + 80 = 81\ x_1 = (-1-9)/20 = -1/2 = -0.5,\ x_2 = (-1+9)/20=8/20 = 0.4$