Question

решите номер 6 пожалуйста очень срочно!!!!

Answer 1

$27^{frac{2}{3}}*16^{frac{1}{4}}-64^{frac{2}{3}}=(3^3)^{frac{2}{3}}*(2^4)^{frac{1}{4}}-(4^3)^{frac{2}{3}}=3^2*2-4^2=9*2-16=2$

 

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