Question

1/x-2-x/1+2=0
решите уравнение

Answer 1

1/(х -2) - х/ (1 +2) = 0
1(х-2) - х/3 = 0
3(х -2) - х (х-2) = 0
3х - 6 - х^2 + 2x = 0
-x^2 + 5x - 6 = 0
x^2 - 5x + 6 = 0
D = 25 -4*6 = 25 - 24 = 1    √D = 1
x1 = (5 + 1) / 2 = 3
x2 = (5 - 1) / 2 = 2
Ответ: х1 = 3; х2 = 2