Question

решите квадратное уравнение : 3 1/3u^2 + 3u - 3 = 0

Answer 1

 

$(3frac{1}{3})u^2 + 3u - 3 = 0\ (10/3) u^2 + 3u - 3 = 0 | *3\ 10 u^2 + 9u - 9 = 0\ D = 81 + 4 * 9 * 10 = 81 + 360 = 441\ u_1 = (-9 + 21)/20 = 12/20 = 3/5\ u_2 = (-9 - 21)/20 = -3/2$