Question

sin(п2-п4)cos(3п2-п4)tg(п+п6)

Answer 1

=cos(π/4)*(-sin(π/4))*tg(π/6)=
$= frac{ sqrt{2} }{2}*(- frac{ sqrt{2} }{2} )* frac{ sqrt{3} }{3}=- frac{2 sqrt{3} }{12}=- frac{ sqrt{3} }{6}$