Question

(x-1)(x2+6x+9)=x2+12x+27

Answer 1

$(x-1)( x^{2} +6x+9)= x^{2} +12x+27 \ x^{3} + 6x^{2} +9x- x^{2} -6x-9- x^{2} -12x-27=0 \ x^{3} + 4x^{2} -9x-36=0 \ x^{2} (x+4)-9(x+4)=0 \ ( x^{2} -9)(x+4)=0 \ 1)x^{2} -9=0 \ x^{2} =9 \ x1=3 \ x2=-3 \ 2)x+4=0 \ x3=-4$

Answer 2

спасибо)

Answer 3

не за что