Question

0.5у×(2у-1)-(0.5-2у)+1=0

Answer 1

$0.5y(2y-1)-(0.5-2y)+1=0$
$y^{2} -0.5y-0.5+2y+1=0$
$y^{2} +1.5y+0.5=0$
$2y^{2} +3y+1=0$
$D=9-8=1$
$y1= frac{-3+1}{4} =-0.5$

Answer 2

y2=(-3-1)/4=-1