Question

(u-4)(4+1)+(4^2-4+1)(4+1) преобразуйте в многочлен.

Answer 1

$(u-4)(4+1)+(4^2-4+1)(4+1)=\(4+1)((v-4)+(4^2-4+1))=\(4+1)(v-4+4^2-4+1)=5(v-9)=5v+45$

 

$<var>(u-4</var><var>)(u+1)+(u^2-u+1)(u+1)=\</var><em><var> (u+1)(u-4+u^2-u+1)=\ (u+1)(u^2-3)=\ u^3+u^2-3u-3</var></em>$

Answer 2

(u-4)(4+1)+(4^2-4+1)(4+1) = (4+1)(4^2-4+1+u-4)=5(9+u)=45+5u