Question

(2y/3x-3x/2y):(2y+3x) при х=1/3,y=1/4

Answer 1

(4y^2-9x^2)/3x2y):(2y+3x)=(2y-3x)(2y+3x)/3x2y) *1/(2y+3x)=(2y-3x)/3x2y= (2*1/4-3*1/3)/1/2=(1/2-1)/0.5= -0.5/0.5= -1

Answer 2

4у²-9у²/6ху Х 1/2у+3х=
(2у+3х)(2у-3х)/6ху Х 1/2у+3=
=2у-3х/6ху= 2(1/4) +3(1/3)/ 6(1/12)=3
=