Question

Помогите решить неравенство

$log_{2-x} (x+2)* log_{x+3} (3-x) leq 0$

Answer 1

$log_{2-x}{x+2}*log_{x+3}{3-x} leq 0 rightarrow \ rightarrow \ (1-x)(x+1)(x+2)(2-x) leq0 \ x=б1;б2 \ -(-2) +(-1) -(1) +(2) - znaki \ x in [-2;-1] cup [1;2] \ ODZ : \ 2-x textgreater 0 ; x textless 2; 2-x neq 0 ; x=1 \ x+2 textgreater 0; x textgreater -2\ x+3 textgreater 0 ; x textgreater -3 ; x+3 neq 0 ; x neq -2 \ 3-x textgreater 0 ; x textless 3 \ x in (1;2)$