Question

Помогите решить!!!)))
4x^2=7x-3.
2x^2+5=-7x

Answer 1

1.)  $4 x^{2} -7x+3=0$
$x_{1,2} = frac{7+- sqrt{49-48} }{8}$
$x_{1} = frac{7+1 }{8} =1$
$x_{2} = frac{7-1}{8}= frac{6}{8} = frac{3}{4} =0,75$
2.)  $2 x^{2} +7x+5=0$
$x_{1,2} = frac{-7+- sqrt{49-40} }{4}$
$x_{1} = frac{-7+3}{4}= -1$
$x_{2} = frac{-7-3}{4}= - frac{10}{4} =-2,5$

Answer 2

спасибо!!!!

Answer 3

4x²=7x-3                D=b²-4ac
4x²-7x+3=0
a=4 b=-7 c=3
D=(-7)²-4×4×3=49-48=1  √D=1
x₁=7-1/2×4=6/8=3/4
x₂=7+1/2×4=8/8=1

2x²+5=-7x
2x²+7x+5=0
a=2 b=7 c=5
D=7²-4×2×5=49-40=9 √D=3
x₁=-7-3/2×2=-10/4=-5/2
x₂=-7+3/2×2=-4/4=-1