Question

$x^{2} +(1- sqrt{10} )x- sqrt{10} leq 0$

Answer 1

$x^2+(1- sqrt{10)} x- sqrt{10} leq 0$
$D=(1- sqrt{10)} ^2+4* sqrt{10} =(1+ sqrt{10})^2$
$x_{1} = frac{ sqrt{10}-1+1+ sqrt{10} }{2} = sqrt{10 \ }$
$x_{2} = frac{ sqrt{10}-1-1- sqrt{10} }{2} =-1$
x∈[-1;√10]