Question

3^x*2^y=576

log√2(y-x)=4

систему пожалуйста

Answer 1

3^(x^2 + y^2) = 81
log 2(x) + 2log 4(y) = 1 
3^(x^2 + y^2) = 3^3
log 2(x) + 2log (2^2) (y) =1 
x^2 + y^2 = 3
log 2(x) + 2/2 * log 2(y) = 1 
x^2 + y^2 = 3
log 2(xy) = 1 
x^2 + y^2 = 3
2^1 = xy 
x^2 + y^2 = 3
xy = 2 
x = 2/y
(2/y) * y = 2 
2 = 2 => x и у - любые числа, не = 0