Question

x^2/x+3=1/4 срочнооооо

Answer 1

$frac{x^2}{x+3}= frac{1}{4} \ (x+3)=4x^2\4x^2-x-3=0\ D=b^2-4ac=(-1)^2-4*4*(-3)=1+48=49\ x_1= frac{-b+ sqrt{D} }{2a}= frac{1+ sqrt{49} }{8} = frac{1+7}{8} =1\ x_2= frac{-b- sqrt{D} }{2a} = frac{1- sqrt{49} }{8} = frac{1-7}{8} = frac{-6}{8}=-0.75$
Ответ: $1;-0.75$