Question

Решите пожалуйста до 16:00 срочно 1068 срочно с координатами пж

Answer 1

$1 leq frac{5}{2} + frac{x}{2} textless 2.5$
1-5/2≤x/2<2.5-5/2
-1.5≤0.5x<0
-3≤x<0
$0 textless frac{2x}{5}+ frac{3}{5} textless 1$
0-3/5<2x/5<1-3/5
-0.6<0.4x<0.4
-1.5<x<1
$2.15 textless frac{3x}{4} - frac{1}{4} textless 2.6$
2.15+1/4<3x/4<2.6+1/4
2.15+0.25<0.75x<2.6+0.25
2.4<0.75x<2.85
2.4/0.75<x<2.85/0.75
3.2<x3.8
-1<3/4x-1/4<2
-1<0.75x-0.25<2
-1+2.5<0.75x<2+2.5
1.5/0.75<x<4.5/0.75
2<x<6